12a^2+12a=12

Solution for 12a^2+12a=12 equation:

12a^2+12a=12

We move all terms to the left:

12a^2+12a-(12)=0

a = 12; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·12·(-12)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{5}}{2*12}=\frac{-12-12\sqrt{5}}{24}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{5}}{2*12}=\frac{-12+12\sqrt{5}}{24}
$